Problem 16 - Power Digit Sum

Problem

This problem comes from Project Euler 16

Problem

$2^{15} = 32768$ and the sum of its digits is $3+2+7+6+8=26$

What is the sum of the digits of the number $2^{1000}$ ?

Solution

The solution I went for was fairly simple.

1. Calculate $2^{1000}$
2. Turn that number into a string first, then an array of integers
3. Sum the array of integers

Code

# Project Euler: Problem 16
# Power digit sum

num = 2**1000
num_list = [int(i) for i in str(num)]
print(sum(num_list))